blog:2023-01-22-xy-2
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blog:2023-01-22-xy-2 [2023/01/23 08:25] – created pzhou | blog:2023-01-22-xy-2 [2023/06/25 15:53] (current) – external edit 127.0.0.1 | ||
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Suppose I build a U brane on the base, and compute its endomorphism. | Suppose I build a U brane on the base, and compute its endomorphism. | ||
- | Let me try something else. $xy(y-1)$. How about this function? Is it better in terms of being more generic? partial $x$ gives $y(y-1)=0$, and partial y gives $x (2y-1)=0$, so we get either $(0,0)$ or $(0,1)$ as singular point, all with singular value $0$. OK, so we have two critical points over the same critical value, it seems they don't talk to each other. | + | Let me try something else. $xy(y-a)$. How about this function? Is it better in terms of being more generic? partial $x$ gives $y(y-a)=0$, and partial y gives $x (2y-1)=0$, so we get either $(0,0)$ or $(0,a)$ as singular point, all with singular value $0$. OK, so we have two critical points over the same critical value, it seems they don't talk to each other. |
- | Is that what happens with $f=xy^2$? | + | Is that what happens with $f=xy^2$? Not quite, here is the trouble, the generic fiber was $\C_y \RM \{y=0, y=a\}$, And it is quite different from $a=0$. Maybe you can kill something, so that it is ok. |
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+ | What's the story for $f=xy$? Say, we are on the boundary $|x|^2+|y|^2=1$, | ||
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+ | Now, we do $2 \theta_y + \theta_x = 0$. Good, suppose we now cone over this Legendrian knot, what can I say? | ||
blog/2023-01-22-xy-2.1674462326.txt.gz · Last modified: 2023/06/25 15:53 (external edit)