Peng Zhou

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blog:2023-02-10 [2023/02/10 20:17] – created pzhoublog:2023-02-10 [2023/06/25 15:53] (current) – external edit 127.0.0.1
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 ====== 2023-02-10 ====== ====== 2023-02-10 ======
-  * Reading about symmetric product, by [[https://lekili.duckdns.org/research/higheraus.pdf | DJK]] and [[https://arxiv.org/pdf/1003.2962.pdf | Auroux's ICM]]+  * Reading about symmetric product, by [[https://lekili.duckdns.org/research/higheraus.pdf | Dykerhoff-Jasso-Lekili]] and [[https://arxiv.org/pdf/1003.2962.pdf | Auroux's ICM]].  
 +  * Idea about generation  
 + 
 +===== Upstairs Skeleton ===== 
 +How to understand it? Downstairs, we have Sym2(C)Sym^2(\C^*), which we can shrink to Sym2(S1)Sym^2(S^1). Upstairs, I just don't know what to put over the diagonal. We know the fiber of the diagonal is C×Cu\C^* \times \C_u, and the superpotential is basically the variable uu, so if we just ask for the fiberwise skeleton, it is zero.  
 + 
 +Same thing, if we ask for the multiplicative case. The fiberwise skeleton of a smooth fiber is (S1)2(S^1)^2, then become subcritical for the special fiber.  
 + 
 + 
 +===== Fiber of W ===== 
 +Consider the simple case. Hilbhor2(CxC)Hilb^2_{hor}(C^* x C), where $W = y_1^2 + y_2^2 + (x_1- x_2)/(y_1-y_2).Wereduceit.Let. We reduce it. Let A = x_1 + x_2,, B = (y_1-y_2)^2$, $u = (x_1- x_2)/(y_1-y_2)$, and u2BA20u^2 B - A^2 \neq 0. Superpotential is W=B+uW = B + u.  
 + 
 +Or Y=x2y2z0Y = {x^2 - y^2 z \neq 0} and W=y+zW = y + z.  
 + 
 +We need to consider what is the divisor x2y2z=0x^2 - y^2 z = 0 .  
 + 
 +The fiber over ww is C2 {x2y2(wy)=0}C^2 \ \{x^2 - y^2 (w-y) = 0 \} 
 +Is that deleted guy smooth? Namely 
 +xdx(2wy3y2)dy=0 xdx - (2w y - 3y^2) dy = 0  
 +means x=0,y=0x=0, y=0 or x=0,y=2w/3x=0, y= 2w/3. So, what happens here? when w=0w=0, the two critical points in the deleted divisor merge. What do you want to delete to make the complement the vanishing cycle the same?  
 + 
 +Fiber better be R^2
  
  
blog/2023-02-10.1676060277.txt.gz · Last modified: 2023/06/25 15:53 (external edit)