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--- blog:2023-02-24 [2023/02/25 09:43] – [Forget the window for now] pzhou
+++ blog:2023-02-24 [2023/06/25 15:53] (current) – external edit 127.0.0.1
@@ Line 74: / Line 74: @@
 But, how do I know if there is a part of the skeleton that should be removed? maybe we have a skeleton model that has no obvious part needs to be removed.
+===== But why the wrong answer works?  =====
+In the skeleton approach, there is nothing explicit wrong, it is only my viewpoint is wrong, which is internal to me.
+However, on the A-side,  when we make the size of the coefficient really big or small, then take the fiber, it indeed have the correct tropical image. The tropical limit is what I want.
+Consider the example of $\C^3 / \C^*$ by weight (1,1,-1). Then, $t = xy/z$, and $W = x + y + xy/t$. The fiberwise $W$ always are well-defined, for $t \neq 0$. There is no special moment in $t$ (weird!) OK, maybe when $t = 0$, then $W$ become $x + y + xy/t$, hence mirror is $Tot(O(-1))$. And for $t=\infty$, $W =x + y$.
+The A-side fiber always matches the 'most positive' GIT chamber, in the above it is $Tot(O(-1))$.