Peng Zhou

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blog:2023-03-22 [2023/03/23 08:26] – created pzhoublog:2023-03-22 [2023/06/25 15:53] (current) – external edit 127.0.0.1
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 Aha! How about this: Aha! How about this:
-$$ x = \frac{t}{1-t}, \quad y = \frac{1/t}{1-1/t} = \frac{1}{1} $$ +$$ x = \frac{t}{1+t}, \quad y =   \frac{1}{1+t} $$ 
-thus $+ y = -1OK, good enough+ 
 +We can put a Kahler metric on this. By first do a semi-tropicalization, then, put the attracting center at $|x| = |y| \gg 1$. Since things are really symmetric, I will get that skeleton, for this case.  
 + 
 +This is the case where $B = \R \Z = S^1$, and $H = \{0\\In B$. Then, $B_{\C} = \C^*$. Fine.  
 + 
 +No, not fine. I want something not like this. I want to say, my skeleton is $B$. And then I made an infinitesimal, very much local, real blow-up.  
 + 
 +I want to change my Liouville form only locally. How should I change my $\varphi$ (which was previously just $\rho^2$.) What if I add to $\varphi$, a compactly supported function $\eta( r)$,  
 + 
 +OK, this is actually pretty good. Let $\eta \in [-R,R], \phi \in [0, 2\pi]$, and we consider $\epsilon e^{\eta + i \phi}$, framing the $\epsilon$-scale annuli. We have, where $\eta=1$, a function which is $[\epsilon e^\eta \cos(\phi)]^2$. Then, we can extend that to a function of the form $\eta^2 - C$ near $\eta=0$. OK, do-able. How do you put a puncture?  
 + 
 +Say you used to have $\omega = dx dy$, now you need to change it to $(1 F(r)) dx dy$. You previously have $\lambda = dx$, now you need to change it to $F(r) r dr d \theta d ( G(r) d \theta) $ where $G(r) d \theta$ is a well-defined 1-form.  
 + 
 + 
 +OK, I think this can be done in a local way 
 + 
 +==== 2 dim ==== 
 +Of course, the simplest way is to do a product. What's the local model? $\R^2$, $T^*\R^2$. What's the local model? Cylinder with two stops at one end. The neighborhood and thickening is nice.  
 + 
 + 
 +What happens, if you have 3 lines come together? Is there some parameter? I don't think so. Here is the reason. You can define skeleton basically by erecting a conormal, then put a lollipop at the end. There is no ambiguity at putting a lollipop. And if you have several such lollipop, these lollipops are disjoint.  
 + 
 + 
 +==== non-unimodular case? quotient? ==== 
 + 
 +How to describe the upstair space $(t-1)^2 = uv$, and $(t-1) = (uv)^2$, and $t^2 - 1 = uv$? Maybe the first one is more serious. You can deform it, to $(t-1)(t-1-\epsilon)=uv$, or you can resolve it. I guess, we want to deform it.  
 + 
 +suppose we have several copies of this space, and we want to do multiplicative reduction, what do we do? We  
 +consider certain product, like $t_1 t_2 t_3^2 = b$ (say we want to do weighted proj space), and then we quotient out the fiber by something.  
 + 
 +Downstairs space, what do we do with the quotient step?  
  
  
blog/2023-03-22.1679559983.txt.gz · Last modified: 2023/06/25 15:53 (external edit)