blog:2023-06-10
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====== 2023-06-10 ====== | ====== 2023-06-10 ====== | ||
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+ | * lattice and B-field | ||
===== lattice and B-field ===== | ===== lattice and B-field ===== | ||
Let $\Sigma$ be a Riemann surface. Let $Q$ be a quiver on $\Sigma$, consist of vertices and directed edges. (No edge is contractible to a point, and no two edges are homotopic. ) | Let $\Sigma$ be a Riemann surface. Let $Q$ be a quiver on $\Sigma$, consist of vertices and directed edges. (No edge is contractible to a point, and no two edges are homotopic. ) | ||
- | Fix a hermitian vector bundle $E$ over $\Sigma$ with connection $\nabla$. | + | Fix a hermitian vector bundle $E$ over $\Sigma$ with unitary |
We define the Hilbert space to be $\gdef\hcal{\mathcal H}$ | We define the Hilbert space to be $\gdef\hcal{\mathcal H}$ | ||
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We define a sesquilinear form | We define a sesquilinear form | ||
- | $$H(s_1, s_2) = \la s_1, s_2 \ra + \la \Phi(s_1), s_2 \ra $$ | + | $$H(s_1, s_2) = \langle |
+ | Since $ \langle (s_1)_{i \to j}, (s_2)_j \rangle = \langle (s_1)_{i}, (s_2)_{j \to i} \rangle$. | ||
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+ | Well, this only says, we have a graph. We label the vertices with hermitian vector spaces and label the edges with isometries. We can ask for the spectrum of this system. | ||
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+ | Given two such system, we can form a tensor product. Hence, we can tensor by another line bundle, or even vector bundle. | ||
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+ | Let $Loc_{U(1)}(\Sigma)$ be the space of $U(1)$ local system on $\Sigma$, which is a real $2b_1$ torus $T^{b_1}$, $T=S^1$. The spectrum depends on the parameters. | ||
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+ | Can one find some special solvable model? | ||
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+ | ===== Summary ===== | ||
+ | Let $Q$ be a graph on a surface $S$ of genus $g$. | ||
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+ | To each node, we associate a complex hermitian vector space. Let $V = \oplus_i V_i$, then $V$ is a hermitian vector space. Consider a hermitian form | ||
+ | $$ B: V \times V \to \C $$ | ||
+ | such that | ||
+ | $$ B(v, w) = \overline{B(w, | ||
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+ | If we equip $S$ with a flat $U(1)$ connection on a trivial line bundle, then we can twist the hermitian form. And, we can ask for the spectrum of the twisted matrix. It is a function on $T^{2g}$, but maybe we can extend it to a function on $(\C^*)^{2g}$. This is the generalization of the Fourier transformation. | ||
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+ | Now, we can turn on an ' | ||
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+ | ===== Discussion with Haiwen ===== | ||
+ | How to solve the 1D spin chain cycle. | ||
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blog/2023-06-10.1686472636.txt.gz · Last modified: 2023/06/25 15:53 (external edit)