Peng Zhou

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blog:2023-06-20 [2023/06/20 20:21] pzhoublog:2023-06-20 [2023/06/25 15:53] (current) – external edit 127.0.0.1
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 ====== 2023-06-20 ====== ====== 2023-06-20 ======
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 +  * muse on euler class
 +
 +===== euler class =====
  
 Yesterday I read about BFN's construction. One thing that strikes me is the appearance of 'euler class' Yesterday I read about BFN's construction. One thing that strikes me is the appearance of 'euler class'
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 +===== what should be true =====
 +first of all, why we choose to use homology instead of cohomology? is it convention, or is it because the space is singular or non-compact? 
 +
 +when we do convolution product, suppose we have a group, a compact Lie group. let me try to formulate it in both ways. 
 +
 +If we use sheaves on compact group, what do I do? let me try to use homology, just bare homology. So, I have a cycle, and another cycle. I take box product, then I pushforward. but pushing forward is intersect with fiber, no that would be restrict to the fiber. Then, what does pushforward mean? Can I pushforward cohomology class? 
 +
 +No, it is not that complicated. Let's consider the matrix model first. Suppose we have $M_1, M_2, M_3$, and correspondences, $Z_{12}, Z_{23}$. assuming properness all around. Say $Z_{12}$ is of codimension $a = n_1+n_2 - d_{12}$, and $Z_{23}$ of codimension $b = n_2+n_3 - d_{23}$. We pullback these classes, take their cup product, so get degree $a+b$ inside $n_1+n_2+n_3$ space, which is of dimension $d_{12}+d_{23}-n_2$, then we just pushforward. 
 +
 +Now, consider the group situation, I want to say, dimension $d_1$ and $d_2$ add up, then you do the product. so it is literally just pushforward under the product. 
 +
 +In our current situation, we have a group $\Z$, and over it we have the bundle of $N$ sections on the ravioli. pretend that it is finite dimensional. For simplicity, we can rigidify. and just consider basis. 
  
  
blog/2023-06-20.1687292471.txt.gz · Last modified: 2023/06/25 15:53 (external edit)