blog:2023-07-26
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blog:2023-07-26 [2023/07/26 20:37] – pzhou | blog:2023-07-26 [2023/07/27 05:59] (current) – [2023-07-26] pzhou | ||
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+ | Declaration: | ||
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* Reading Ginzburg' | * Reading Ginzburg' | ||
* Heisenberg algebra and Weyl algebra (just names) | * Heisenberg algebra and Weyl algebra (just names) | ||
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Just take the 1-dimensional case $n=1$. There is another set of generators, take $a = p-iq, a^\dagger = p+iq$, then $[a, | Just take the 1-dimensional case $n=1$. There is another set of generators, take $a = p-iq, a^\dagger = p+iq$, then $[a, | ||
- | What is Stone-Von Neumann theorem? It says, for $c\neq 0$, there is only one unitary irreducible reprensentation of $h_1$, upto isomorphism. You can either do $L^2(\R)$, and do Harmonic oscillator' | + | What is Stone-Von Neumann theorem? It says, for $c\neq 0$, there is only one unitary irreducible reprensentation of $h_1$, upto isomorphism. |
+ | * You can either do $L^2(\R)$, and do Harmonic oscillator' | ||
+ | * or you can do coherent state, $a = \d_z, a^\dagger = z \cdot $, and the inner product is using the Bargmann-Fock metric. | ||
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+ | ===== $G$-equivariant sheaf vs equivariant coherent sheaf===== | ||
+ | Let $G=GL_n$, a linear algebraic group. | ||
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+ | The claim is, $G$-equivariant sheaf of a point is stupid, just vect; but $G$-equivariant coherent sheaf on a point is very clever. Why? | ||
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+ | First off, we can consider the definition. Let $X$ be a space, we have $p, a: G \times X \to X$. An equivariant sheaf is a sheaf $F$ on $X$, together with the data of an isomorphism $\phi: p^*F \to a^*F$. Now, if $F$ is just a sheaf, then, we just have sheaf pullback, $p^{-1}(F)$ and $a^{-1}(F)$, | ||
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+ | So, no luck? How about $I$-equivariant perverse sheaf on $G(K)/I$? Of course, everything maps. | ||
blog/2023-07-26.1690403879.txt.gz · Last modified: 2023/07/26 20:37 by pzhou