blog:2023-07-26
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blog:2023-07-26 [2023/07/26 20:58] – [stop, why do you go here?] pzhou | blog:2023-07-26 [2023/07/27 05:59] (current) – [2023-07-26] pzhou | ||
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====== 2023-07-26 ====== | ====== 2023-07-26 ====== | ||
+ | Declaration: | ||
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* Reading Ginzburg' | * Reading Ginzburg' | ||
* Heisenberg algebra and Weyl algebra (just names) | * Heisenberg algebra and Weyl algebra (just names) | ||
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* or you can do coherent state, $a = \d_z, a^\dagger = z \cdot $, and the inner product is using the Bargmann-Fock metric. | * or you can do coherent state, $a = \d_z, a^\dagger = z \cdot $, and the inner product is using the Bargmann-Fock metric. | ||
- | ===== stop, why do you go here? ===== | + | ===== $G$-equivariant sheaf vs equivariant coherent sheaf===== |
- | I was formally moving these building blocks here and there, like $G(O)$-equivariant | + | Let $G=GL_n$, a linear algebraic group. |
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+ | The claim is, $G$-equivariant | ||
+ | First off, we can consider the definition. Let $X$ be a space, we have $p, a: G \times X \to X$. An equivariant sheaf is a sheaf $F$ on $X$, together with the data of an isomorphism $\phi: p^*F \to a^*F$. Now, if $F$ is just a sheaf, then, we just have sheaf pullback, $p^{-1}(F)$ and $a^{-1}(F)$, | ||
+ | So, no luck? How about $I$-equivariant perverse sheaf on $G(K)/I$? Of course, everything maps. | ||
blog/2023-07-26.1690405109.txt.gz · Last modified: 2023/07/26 20:58 by pzhou