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--- blog:2024-01-05 [2024/01/06 08:35] – pzhou
+++ blog:2024-01-05 [2024/01/07 01:04] (current) – pzhou
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 ====== 2024-01-05 ======
-In the simplest setting, we have mirror symmetry for $\Coh(\C^* \times \C^2)$.
+In the simplest setting, we have mirror symmetry for $Coh(\C^* \times \C^2)$.
 Next, we are going to take symmetric power.
@@ Line 8: / Line 8: @@
 The key question is: what is the superKLRW algebra?
+From the A-side, let me guess, we have 'fiber product' of two MC. So, when y1 = y2, in the fiber, we need to have x1 = x2, and z1 = z2 (the new pair of fiber coord). And we need to remember the ratio of (x1-x2)/(y1-y2), and (z1-z2)/(y1-y2).