Peng Zhou

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blog:2024-12-25 [2024/12/26 06:49] – created pzhoublog:2024-12-25 [2024/12/26 07:05] (current) pzhou
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 It is about going from $BGL(k_1)$ and $BGL(k_2)$ to $BGL(k)$. I just know $T^{k_1}$ and $T^{k_2}$ merges to $T^{k_1+k_2}$. Let's try parabolic induction: we have It is about going from $BGL(k_1)$ and $BGL(k_2)$ to $BGL(k)$. I just know $T^{k_1}$ and $T^{k_2}$ merges to $T^{k_1+k_2}$. Let's try parabolic induction: we have
-$$ GL(k_1) \times GL(k_2) \gets P_{k_1, k_2} \to GL(k_1+k_2) $$+$$ G_1\times G_2 = GL(k_1) \times GL(k_2) \gets P=P_{k_1, k_2} \to GL(k_1+k_2)=G $$ 
 + 
 +Assume everything is fine, then we have 
 +$$ BP \to B(G_1 \times G_2), \quad BP \to BG $$ 
 +The first one is saying, if you have a principle $P$ bundle $E$ over something $M$, then you can build the associated bundle of $E \otimes_P L$. 
 + 
 +I guess the corresponding construction on sheaf is just doing pull-push along the parabolic induction.  
 + 
 +----- 
 + 
 +Is there classifying space for two step flags? well, one needs to say the ranks, so it would be the $BP_{k_1, k_2}$. 
  
  
blog/2024-12-25.1735195758.txt.gz · Last modified: 2024/12/26 06:49 by pzhou