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notes:2022-11-08-cherednik-on-hecke [2022/11/08 15:52] – created pzhounotes:2022-11-08-cherednik-on-hecke [2023/06/25 15:53] (current) – external edit 127.0.0.1
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 ====== 2022-11-08, Cherednik on Hecke ====== ====== 2022-11-08, Cherednik on Hecke ======
  
-==== Section 1: Hecke algebra in rep theory ====+====1: Hecke algebra in rep theory =====
 very funny comment about real math and imaginary math, one can see he is an concrete guy with feet on ground (i.e. real axis).  very funny comment about real math and imaginary math, one can see he is an concrete guy with feet on ground (i.e. real axis). 
   - What is a zonal spherical function? From wiki, it is a //function on a locally compact group G with compact subgroup K (often a maximal compact subgroup) that arises as the matrix coefficient of a K-invariant vector in an irreducible representation of G.// But why we study it?   - What is a zonal spherical function? From wiki, it is a //function on a locally compact group G with compact subgroup K (often a maximal compact subgroup) that arises as the matrix coefficient of a K-invariant vector in an irreducible representation of G.// But why we study it?
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   - Now, I am really confused and intrigued. These simple-verma coefficients are related to modular representation.    - Now, I am really confused and intrigued. These simple-verma coefficients are related to modular representation. 
  
 +Most of the remaining discussion is too high for me now. Skip it.
  
 +===== 2: affine KZ =====
 +It is a first order differential equation, taking value in an infinite dimensional algebra called ** degenerate affine hecke algebra **
  
 +Here is the equation
 +$$ \frac{\d \Phi}{\d u} = \left( k \frac{s}{e^u - 1} + x \right) \Phi(u) $$
 +  * There is $e^u$, so the solution is like 1-periodic, or if we use $U = e^u$, then it lives on $\C^*$. But we prefer this way, since $\Phi(U)$ will be multivalued. Wait, around $u=0$, will it also have interesting monodromy? 
 +  * $k$ is a parameter $s,x$ are linear operators, such that $$ s^2=1, xs + sx = k. $$ Why we have thse? 
 +  * What?  The above relation among $s,x,k$ generate the $H_{A_1}'$, degenerate affine Hecke of type $A_1$. 
 +  * Now, if we change variable, let $z = e^{-u}$ (as one should), and repackage the equation, we see poles at $z=0, \infty, 1$. But still, this is a complicated equation. However, if we don't solve for the most general curve in the Hecke algebra (indeed, we are looking at a pair-of-pants in the Hecke algebra parameterized by $k$), but rather we take representation of $H_{A_1}'$, then it become much manageable. 
  
 +{{:notes:pasted:20221108-082040.png}}
  
 +OK, too lazy to copy down the formula. A few comments
 +  * $s$ should be a permutation matrix, but here we diagonlized it. Not sure what $x$ should be. 
 +  * When you solve the equation for $\Phi(u)$, or $\Phi(z)$ for $z = e^{-u}$, the first component $\Phi_1(z)$ will be the hypergeometric equation. There are the Poch-hammer symbol $(x)_n$, and series summation. (We should now the series only converge for some range $z$, no?)
  
 +The AKZ equation for $GL_n$. OK, we have 
 +$$ A_i = \sum_{j \neq i} \frac{\Omega_{ij}}{z_i - z_j} $$
 +where $z_i \in \C^*$. So affine means working with $z_i \in \C^*$? why such a big deal? 
 +One need to make them satisfy 
 +$$ \d_j A_i - \d_i A_j - [A_i, A_j] = 0 $$
 +Nothing but the flat connection property. 
 +
 +But, then, what is $\Omega_{ij}$? Is it independent of $z_i$? I guess so, they need to satisfy useful commutation relations. 
 +
 +So, indeed
  
  
notes/2022-11-08-cherednik-on-hecke.1667922722.txt.gz · Last modified: 2023/06/25 15:53 (external edit)