Peng Zhou

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blog:2023-09-16 [2023/09/16 14:41] – created pzhoublog:2023-09-16 [2023/09/16 22:41] (current) pzhou
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-The removing strand operator is not that simpletaking intersections, and putting in the object. There must be some interesting differentials correcting it.+The removing strand operator is not that simpletaking intersections, and putting in the object. There must be some interesting differentials correcting it.
  
-I don't know about q-degreebut cohomological degree should be matchedFor all that I care about, the holomorphic volume form is like $( \prod_{i<j} (y_i y_j) )(\prod_i dy_i)$+Let $L^k$ be a k-tuple of Lagrangians in $\Sym^k(\Sigma)$avoiding a stop. Let $E$ be the raising operator, i.e., $F$ the lowering operator. Let $F$ be adding a brane, by adding a T-brane, and $E$ be $Hom(T, -)$. (note the change of notation).
  
 +Then, $F$ is easy to achieve, thanks to the stop, we can just add a brane there. But, $E$, its right-adjoint, is a bit difficult. The adjoint condition basically involves solving an equation. What we want, is a concrete, purely Fukaya category like functor. 
  
 +===== Removing a Strand =====
 +If we are just dealing with $gl(1|1|)$ quiver Hecke algebra, then it is a purely algebraic game. 
  
 +In the case of T-brane, on a disk with two stops (linear KLR), the problem is completely solved. We just have $k$ output with degree $0, -1, \cdots, 1-k$, with the $i$-th term maps to the $i-1$-th term, with the obvious map. $q$-degree can be deduced.
 +
 +But, what is the holomorphic disk counting proof? And, what if we have something other than a T-brane? You cannot just say how it acts on object. 
 +
 +Indeed, suppose we have a test object $L'$ with $(k-1)$-tuple of disjoint Lagrangian, and we have $L' + T$ hom to some $L^k$. There is a clear count of all possible intersections. Here already, we have differentials, it is not possible to eliminate differentials. The differential can involve a $T$-intersection point, or not. If it does, then we need to explicitly remember it. 
 +
 +However, this depends on a choice of a test object, and the disk counting uses that test object. Is there a universal test object? Let me draw some examples with different test objects. 
  
  
blog/2023-09-16.1694875301.txt.gz · Last modified: 2023/09/16 14:41 by pzhou